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3n^2-7n-110=0
a = 3; b = -7; c = -110;
Δ = b2-4ac
Δ = -72-4·3·(-110)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-37}{2*3}=\frac{-30}{6} =-5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+37}{2*3}=\frac{44}{6} =7+1/3 $
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